Vamshi - Maths tutor - Kota
1st lesson free
Vamshi - Maths tutor - Kota

Vamshi's profile, qualifications and contact details have been verified by our experts

Vamshi

  • Rate S$8
  • Response 1h
  • Students

    Number of students accompanied by Vamshi since their arrival at Superprof

    2

    Number of students accompanied by Vamshi since their arrival at Superprof

Vamshi - Maths tutor - Kota
  • 5 (1 review)

S$8/h

1st lesson free

Contact

1st lesson free

1st lesson free

  • Maths
  • Physics
  • Trigonometry
  • Geometry
  • Logic

Mechanical Engineering Graduate from IIT GOA. Also an expert in solving both Maths and Physics problems (Had experience in teaching Physics to students preparing for JEE)

  • Maths
  • Physics
  • Trigonometry
  • Geometry
  • Logic

Lesson location

About Vamshi

I'm a mechanical engineering graduate from IIT Goa. I want to help the students who are preparing for JEE and NEET. As I myself a student who once prepared for JEE, want to share the tips and tricks to help students solve JEE problems.

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About the lesson

  • Primary
  • Secondary
  • SPM
  • +8
  • levels :

    Primary

    Secondary

    SPM

    Form 6

    STPM

    Adult education

    Bachelor

    Masters

    Diploma

    Doctorate

    Other

  • English

All languages in which the lesson is available :

English

Coming to Physics I can teach you by taking real life examples and teach you methods that are easy to understand and are efficient.

And coming to Maths try to solve the below question efficiently without using differentiation.
Q) Find the minimum of the given expression:
√((a)^2 + (b)^2) + √((a - 5)^2 + (b - 5)^2)

I'm sure that I can help you solve the above problem efficiently which will take only a minute to solve. Not only above problem, but I can help you solve many more questions efficiently .

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Rates

Rate

  • S$8

Pack rates

  • 5h: S$40
  • 10h: S$80

online

  • S$8/h

free lessons

This first lesson is free to allow you to get to know your teacher so that they can best meet your needs.

  • 1hr

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